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Apna Merit

FAST Aggregate Calculator 2026

Computing: 50% test + 40% FSc + 10% Matric · Engineering: 33% + 50% + 17%

Updated

The FAST-NUCES aggregate for BS Computing = 50% admission test + 40% FSc (HSSC) + 10% Matric; for BS Engineering it is 33% test + 50% FSc + 17% Matric, per FAST's eligibility criteria. Example: 60% test, 950/1100 FSc and 1000/1100 Matric give 73.64% for computing. Enter your marks below. Official source

BS Computing (CS, AI, Data Science, Cyber Security, Software Engineering)
out of
Weight 50%
out of
Weight 40%
out of
Weight 10%

Formula source: official notice

FAST aggregate formula: BS Computing (CS, AI, Data Science, Cyber Security, Software Engineering)
PartWeightUsual total marks
Admission test score in % (FAST / NTS NAT)50%100
FSc / HSSC40%1100
Matric / SSC10%1100
FAST aggregate formula: BS Engineering (Civil, Electrical, Computer)
PartWeightUsual total marks
Admission test score in % (FAST / NTS NAT-IE)33%100
FSc / HSSC50%1100
Matric / SSC17%1100

How is the FAST aggregate calculated?

FAST-NUCES uses two formulas, set on its official eligibility criteria page:

FAST aggregate weights by program group
Program groupAdmission testHSSC (FSc)SSC (Matric)
BS Computing (CS, AI, Data Science, Cyber Security, Software Engineering)50%40%10%
BS Engineering (Civil, Electrical, Computer)33%50%17%

The admission test can be FAST's own test or NTS NAT (NAT-IE for engineering, NAT-ICS or NAT-IE for computing). Enter your test score as a percentage, or type your marks and change the total. For HSSC, FAST uses Part I and II marks, or Part I alone if Part II is not out when the merit list is compiled.

Worked example (BS Computer Science)

FAST computing aggregate worked example
PartMarksWeightShare
Admission test60 / 10050%30.0000
FSc950 / 110040%34.5455
Matric1000 / 110010%9.0909
Aggregate100%73.64%

The same marks give 78.44% on the engineering formula, because FSc and Matric carry more weight there.

What is the FAST closing merit?

FAST does not publish program-wise closing merits; its eligibility page says merit cut-off marks are determined by the university. Figures you see on other websites are estimates, so we do not show them. Eligibility is 60% in SSC and 60% in HSSC for engineering, or 50% in HSSC for computing.

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Frequently asked questions

What is the FAST aggregate formula for computing programs?

BS Computer Science, AI, Data Science, Cyber Security and Software Engineering use 50% admission test, 40% HSSC and 10% SSC.

What is the FAST formula for engineering?

BS Civil, Electrical and Computer Engineering use 33% admission test, 50% HSSC and 17% SSC.

Which test does FAST accept?

FAST's own admission test or NTS NAT (NAT-IE for engineering; NAT-IE or NAT-ICS for computing). Test results from other universities are not accepted.

Which FSc marks does FAST use?

HSSC Part I and II marks, or Part I alone if Part II is not available when the merit list is compiled. A-level students use their IBCC equivalence.

What is the FAST closing merit?

FAST does not publish program-wise closing merits; the university determines merit cut-offs each year. Figures on other websites are estimates.

FAST ka aggregate kaise nikalain?

Computing ke liye test ka 50%, FSc ka 40% aur Matric ka 10% jama karein. Engineering ke liye test 33%, FSc 50% aur Matric 17%.

FAST mein admission ke liye kitne FSc marks chahiye?

Engineering ke liye Matric aur FSc dono mein 60%, computing ke liye Matric mein 60% aur FSc mein 50%.

Asaan alfaaz mein (Roman Urdu)

FAST ke do formule hain: computing (CS, AI, SE waghera) mein test 50%, FSc 40%, Matric 10%, aur engineering mein test 33%, FSc 50%, Matric 17%.

Misaal: test 60%, FSc 950/1100 aur Matric 1000/1100 ho to computing aggregate 73.64% aur engineering aggregate 78.44% banta hai.

Sources