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UET Peshawar Aggregate Calculator 2026

Official formula: 50% entrance test + 40% FSc Part-I + 10% Matric

Updated

The UET Peshawar aggregate for BSc Engineering = 50% entrance test + 40% Intermediate Part-I (adjusted marks) + 10% SSC, per the UG Prospectus 2026-27. The test has 100 one-mark MCQs. Example: 70/100 test, 480/550 Part-I and 1000/1100 Matric give 79.00%. Enter your marks below. Official source

BSc Engineering (ETEA / entrance test)
out of
Weight 50%
out of
Weight 40%
out of
Weight 10%

Formula source: official notice

UET Peshawar aggregate formula: BSc Engineering (ETEA / entrance test)
PartWeightUsual total marks
Entrance test50%100
FSc Part-I (adjusted marks)40%550
Matric / SSC10%1100
UET Peshawar aggregate formula: BS Computer Science (no entry test)
PartWeightUsual total marks
FSc Part-I (adjusted marks)60%550
Matric / SSC40%1100

How is the UET Peshawar aggregate calculated?

UET Peshawar's UG Prospectus 2026-27 (Admission Rules, "Determination of Merit" 6.1) sets the BSc Engineering merit as entrance test 50% + Intermediate Part-I (adjusted marks) 40% + SSC 10%.

  • Test share = entrance test marks ÷ 100 × 50
  • FSc share = Part-I marks ÷ Part-I total × 40
  • Matric share = SSC marks ÷ SSC total × 10

The 2026-27 engineering entrance test has 100 MCQs (Physics 40, Mathematics 35, English 15, Chemistry or Computer Science 10), one mark each and no negative marking, so the calculator uses 100 as the test total. Pre-medical candidates sit a 65-MCQ paper whose 65 marks count as 100%: enter your marks out of 65 by changing the total.

BS Computer Science has no entrance test: 40% SSC + 60% Intermediate Part-I (prospectus, BS programmes 6.1). Pick it in the formula box.

Worked example

UET Peshawar BSc Engineering aggregate worked example
PartMarksWeightShare
Entrance test70 / 10050%35.0000
FSc Part-I480 / 55040%34.9091
Matric1000 / 110010%9.0909
Aggregate100%79.00%

Adjusted marks, Hafiz-e-Quran and DAE

"Adjusted marks" means UET Peshawar deducts marks for repeated or improved papers (rule 6.3, at most 20 marks), and candidates who take Mathematics as an additional subject lose 10 marks. A Hafiz-e-Quran candidate who passes the university's Hifz test gets an additional 20 marks. DAE holders are judged on their 1st and 2nd year diploma marks for the 40% part.

Where is the UET Peshawar closing merit?

UET Peshawar displays revised merit lists on the main campus notice board, and we have not found an official program-wise closing merit online yet. We will add a UET Peshawar merit list only from an official document; until then, compare your aggregate with UET Taxila closing merits as a rough guide.

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Frequently asked questions

What is the UET Peshawar aggregate formula?

For BSc Engineering: 50% entrance test, 40% Intermediate Part-I (adjusted marks) and 10% SSC, according to the UG Prospectus 2026-27.

How many marks is the UET Peshawar entrance test?

For 2026-27 the engineering paper has 100 MCQs, one mark each, with no negative marking. The pre-medical paper has 65 MCQs, and 65 marks count as 100%.

What is the BS Computer Science formula at UET Peshawar?

BS Computer Science has no entrance test: 40% SSC and 60% Intermediate Part-I (adjusted marks).

What are adjusted marks?

UET Peshawar deducts marks for papers passed in a later attempt (at most 20 marks) and 10 marks for Mathematics taken as an additional subject. Hafiz-e-Quran candidates who pass the university's test get 20 extra marks.

Where can I see the UET Peshawar closing merit?

UET Peshawar puts revised merit lists on its main campus notice board. We have not found an official program-wise closing merit online, so we do not show one yet.

UET Peshawar ka aggregate kaise nikalta hai?

Entrance test ka 50%, FSc Part-I ka 40% aur Matric ka 10%. Har marks ko total se divide karein, weight se multiply karein aur jama kar lein.

Kya UET Peshawar ke test mein negative marking hai?

Nahi. 2026-27 ke prospectus ke mutabiq har sahi jawab ka aik mark hai aur negative marking nahi hai.

Asaan alfaaz mein (Roman Urdu)

UET Peshawar BSc Engineering ka formula: entrance test 50%, FSc Part-I 40% aur Matric 10%. Test 100 MCQs ka hai, negative marking nahi.

Misaal: test 70/100, Part-I 480/550 aur Matric 1000/1100 ho to aggregate 79.00% banta hai. BS Computer Science mein test nahi: Matric 40% aur Part-I 60%.

Sources